(4/(x-1))+(5/(2x^2-8x+6))

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Solution for (4/(x-1))+(5/(2x^2-8x+6)) equation: 


D( x )

2*x^2-(8*x)+6 = 0

x-1 = 0

2*x^2-(8*x)+6 = 0

2*x^2-(8*x)+6 = 0

2*x^2-8*x+6 = 0

2*x^2-8*x+6 = 0

DELTA = (-8)^2-(2*4*6)

DELTA = 16

DELTA > 0

x = (16^(1/2)+8)/(2*2) or x = (8-16^(1/2))/(2*2)

x = 3 or x = 1

x-1 = 0

x-1 = 0

x-1 = 0 // + 1

x = 1

x in (-oo:1) U (1:3) U (3:+oo)

4/(x-1)+5/(2*x^2-(8*x)+6) = 0

4/(x-1)+5/(2*x^2-8*x+6) = 0

2*x^2-8*x+6 = 0

2*x^2-8*x+6 = 0

2*(x^2-4*x+3) = 0

x^2-4*x+3 = 0

DELTA = (-4)^2-(1*3*4)

DELTA = 4

DELTA > 0

x = (4^(1/2)+4)/(1*2) or x = (4-4^(1/2))/(1*2)

x = 3 or x = 1

2*(x-1)*(x-3) = 0

4/(x-1)+5/(2*(x-1)*(x-3)) = 0

(2*4)/(2*(x-1))+5/(2*(x-1)) = 0

2*4+5 = 0

13 = 0

13/(2*(x-1)) = 0

13/(2*(x-1)) = 0 // * 2*(x-1)

13 = 0

x belongs to the empty set

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